360t^2-490=0

Solution for 360t^2-490=0 equation:

360t^2-490=0

a = 360; b = 0; c = -490;
Δ = b2-4ac
Δ = 02-4·360·(-490)
Δ = 705600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{705600}=840$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-840}{2*360}=\frac{-840}{720}
=-1+1/6
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+840}{2*360}=\frac{840}{720}
=1+1/6
$